Topics tagged with phy301

PHY301 Assignment 2 Solution and Discussion

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@zareen said in PHY301 Assignment 2 Solution and Discussion: Label and identify meshes in given below circuit. Use Loop/Mesh analysis to find currents through all Meshes. https://youtu.be/j8LHrm3_brk

PHY301 Assignment 1 Solution and Discussion

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Spring 2020_PHY301_1_SOL.pdf

PHY301 GDB 1 Solution and Discussion

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@zareen said in PHY301 GDB 1 Solution and Discussion: what types of charges are responsible for flow of current in each matter? Insulators and conductors can be solid, liquid or gas, and in some exceptions like glass (solid) which is an insulator becomes conductors when melted at the higher temperature. On the other hand, semiconductors are present in the solid form. Liquids can be conductors or insulators, depends on other properties. Though absolute pure water is an insulator, the liquid metals are electrically conductive. Gases also become electrically conductive when ionized, though they usually are insulators. Conductivity is the phenomenon of transmitting something like heat, electricity or sound. So, based on the conductivity of any material and the presence of a forbidden gap, they (materials) can be classified as conductors, semiconductors or insulators. In the article, we will be differentiating the three terms concerning other points on which they vary. https://youtu.be/17EhKw2tsu4

PHY301 Assignment 2 Solution and Discussion

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Assignment 2(Fall 2019)
Circuit Theory (Phy301)
Marks: 20
Due Date: Jan 17, 2020
DON’T miss these important instructions:

• To solve this assignment, you should have good command over first 28 lectures.
• Upload assignments properly through LMS, (No Assignment will be accepted through email).
• Write your ID on the top of your solution file.
• All students are directed to use the font and style of text as is used in this document.
• Don’t use colorful back grounds in your solution files.
• Use Math Type or Equation Editor etc for mathematical symbols.
• No excuse will be accepted by anyone if found to be copying or letting others copy.
• Don’t wait for the last date to submit your assignment.
• You can draw circuit diagrams in “Paint” in “Corel Draw” or in “circuit maker”. The simple and easy way is to copy the given image in Paint and do the required changes in it.

Q. NO. 1
Find Vo using the source transformation method in the network given below. Label and draw each step where it required. Write each step of the calculation to get maximum marks and also mention the units of each derived value.

Q. NO. 2
Using the Thévenin’s theorem, determine VO across terminals in the circuit network. Show each step of calculation otherwise you will lose your marks. Draw and label the circuit diagram of each step and also mention the units of each derived value.

PHY301 Assignment 1 Solution and Discussion

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Q. 1 Solution: Starting from lower side of circuit network, we can see that 2Ω and 2Ω are in series, so their combined effect is 2+2=4Ω [image: lfQL20V.png] This 4Ω is in parallel of 4Ω to lower side, so their equivalent is [image: LscVakS.png] [image: 7WeFVMO.png] This 2Ω is in series of 5Ω and 1Ω, so the sum of series resistances is 2Ω+ 5Ω+1Ω=8Ω [image: 0SX12Sg.png] Now at upper side, 4Ω and 2Ω are in series 4Ω+ 2Ω=6Ω [image: 7VE1yYt.png] This 6Ω is in parallel of 6Ω, so their equivalent is [image: MPO7UBq.png] [image: RaGW8hK.png] This 3Ω is in series of 3Ω and 1Ω, so the sum of series is 3Ω+ 3Ω+1Ω=7Ω [image: URCiEIC.png] Now we can see 7Ω becomes in series of 8Ω, so equivalent resistance is Req =7Ω + 8Ω Req=15Ω Q.2 Solution: 1) To calculate the source current Is, Firstly, we calculate the total resistance RT= R1+R2+R3 =6Ω V=IR IS=VS/RT = 12/6 =2A 2) Since all resistances are in series, same 2A current pass through each resistance. V1= R1IS =12 =2V V2=R2Is =22 =4V V3=R3IS = 32 =6V 3) P1 =I2R1 = (2)2 *1 =4W P2 =I2R2 = (2)2 *2 = 8W P3 =I2R3 =(2)2 *3 = 12W = 12W 4)- Ps = VsIs P =122 =24 W PT=P1+P2+P3 or PT=I2RT =4+8+12 =24 W