<?xml version="1.0" encoding="UTF-8"?><rss xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:content="http://purl.org/rss/1.0/modules/content/" xmlns:atom="http://www.w3.org/2005/Atom" version="2.0"><channel><title><![CDATA[MTH603 Quiz 1 Solution and Discussion]]></title><description><![CDATA[<p dir="auto">Please share your Quiz</p>
]]></description><link>https://community.secnto.com//topic/1203/mth603-quiz-1-solution-and-discussion</link><generator>RSS for Node</generator><lastBuildDate>Mon, 08 Jun 2026 19:04:39 GMT</lastBuildDate><atom:link href="https://community.secnto.com//topic/1203.rss" rel="self" type="application/rss+xml"/><pubDate>Fri, 24 Jan 2020 17:23:38 GMT</pubDate><ttl>60</ttl><item><title><![CDATA[Reply to MTH603 Quiz 1 Solution and Discussion on Fri, 24 Jan 2020 17:25:38 GMT]]></title><description><![CDATA[<p dir="auto">To improve the accuracy of the derivative of the function, which of the following method is more helpful? MTH603</p>
<p dir="auto"><strong>Extrapolation</strong><br />
Interpolation<br />
Divided difference<br />
Central difference</p>
]]></description><link>https://community.secnto.com//post/3206</link><guid isPermaLink="true">https://community.secnto.com//post/3206</guid><dc:creator><![CDATA[zareen]]></dc:creator><pubDate>Fri, 24 Jan 2020 17:25:38 GMT</pubDate></item><item><title><![CDATA[Reply to MTH603 Quiz 1 Solution and Discussion on Fri, 06 Sep 2024 08:28:47 GMT]]></title><description><![CDATA[<iframe width="100%" height="315" src="https://www.youtube.com/embed/6H1ctWI8uQ4" title="YouTube video player" frameborder="0" allow="accelerometer; autoplay; clipboard-write; encrypted-media; gyroscope; picture-in-picture; web-share"></iframe>]]></description><link>https://community.secnto.com//post/7624</link><guid isPermaLink="true">https://community.secnto.com//post/7624</guid><dc:creator><![CDATA[cyberian]]></dc:creator><pubDate>Fri, 06 Sep 2024 08:28:47 GMT</pubDate></item><item><title><![CDATA[Reply to MTH603 Quiz 1 Solution and Discussion on Fri, 31 May 2024 14:35:52 GMT]]></title><description><![CDATA[<p dir="auto">how many eigenvalues will exit corresponding to the function exp(ax)</p>
]]></description><link>https://community.secnto.com//post/7212</link><guid isPermaLink="true">https://community.secnto.com//post/7212</guid><dc:creator><![CDATA[cyberian]]></dc:creator><pubDate>Fri, 31 May 2024 14:35:52 GMT</pubDate></item><item><title><![CDATA[Reply to MTH603 Quiz 1 Solution and Discussion on Fri, 31 May 2024 14:35:29 GMT]]></title><description><![CDATA[<p dir="auto">for a function; y=f(x), if y0, y1 are 2,3</p>
]]></description><link>https://community.secnto.com//post/7211</link><guid isPermaLink="true">https://community.secnto.com//post/7211</guid><dc:creator><![CDATA[cyberian]]></dc:creator><pubDate>Fri, 31 May 2024 14:35:29 GMT</pubDate></item><item><title><![CDATA[Reply to MTH603 Quiz 1 Solution and Discussion on Fri, 31 May 2024 14:35:12 GMT]]></title><description><![CDATA[<p dir="auto">Jacobian Method in Matrix Form<br />
Let the n system of linear equations be Ax = b. Let us <strong>decompose matrix A into a diagonal component D and remainder R such that A = D + R.</strong> Iteratively the solution will be obtained using the below equation.</p>
]]></description><link>https://community.secnto.com//post/7210</link><guid isPermaLink="true">https://community.secnto.com//post/7210</guid><dc:creator><![CDATA[cyberian]]></dc:creator><pubDate>Fri, 31 May 2024 14:35:12 GMT</pubDate></item><item><title><![CDATA[Reply to MTH603 Quiz 1 Solution and Discussion on Fri, 31 May 2024 14:34:48 GMT]]></title><description><![CDATA[<p dir="auto">b) The eigenvalues of a real symmetric matrix <strong>need not be positive</strong>. They can be positive, negative, or even zero, depending on the elements and the specific structure of the matrix.</p>
]]></description><link>https://community.secnto.com//post/7209</link><guid isPermaLink="true">https://community.secnto.com//post/7209</guid><dc:creator><![CDATA[cyberian]]></dc:creator><pubDate>Fri, 31 May 2024 14:34:48 GMT</pubDate></item><item><title><![CDATA[Reply to MTH603 Quiz 1 Solution and Discussion on Fri, 31 May 2024 14:34:23 GMT]]></title><description><![CDATA[<p dir="auto">Two similar matrices have the same eigenvalues, even though they will usually have different eigenvectors. Said more precisely, if B = Ai’AJ. I and x is an eigenvector of A, then M’x is an eigenvector of B = M’AM. So, A1’x is an eigenvector for B, with eigenvalue ).</p>
]]></description><link>https://community.secnto.com//post/7208</link><guid isPermaLink="true">https://community.secnto.com//post/7208</guid><dc:creator><![CDATA[cyberian]]></dc:creator><pubDate>Fri, 31 May 2024 14:34:23 GMT</pubDate></item><item><title><![CDATA[Reply to MTH603 Quiz 1 Solution and Discussion on Fri, 31 May 2024 14:34:06 GMT]]></title><description><![CDATA[<p dir="auto">an eigenvector v is said to be normalized if the coordinate of largest magnitude is equal to aero?</p>
]]></description><link>https://community.secnto.com//post/7207</link><guid isPermaLink="true">https://community.secnto.com//post/7207</guid><dc:creator><![CDATA[cyberian]]></dc:creator><pubDate>Fri, 31 May 2024 14:34:06 GMT</pubDate></item><item><title><![CDATA[Reply to MTH603 Quiz 1 Solution and Discussion on Fri, 31 May 2024 14:33:50 GMT]]></title><description><![CDATA[<p dir="auto">Let A be an n × n matrix. Then λ = 0 is an eigenvalue of A if and only if there exists a non-zero vector v ∈ Rn such that Av = λv = 0. In other words, 0 is an eigenvalue of A if and only if the vector equation Ax = 0 has a non-zero solution x ∈ Rn.</p>
]]></description><link>https://community.secnto.com//post/7206</link><guid isPermaLink="true">https://community.secnto.com//post/7206</guid><dc:creator><![CDATA[cyberian]]></dc:creator><pubDate>Fri, 31 May 2024 14:33:50 GMT</pubDate></item><item><title><![CDATA[Reply to MTH603 Quiz 1 Solution and Discussion on Fri, 31 May 2024 14:33:37 GMT]]></title><description><![CDATA[<p dir="auto">while using jacobi method fot the matrix A=[1 1/4 1/4 1/4 1/3 1/2 1/3 1/2 1/5]</p>
]]></description><link>https://community.secnto.com//post/7205</link><guid isPermaLink="true">https://community.secnto.com//post/7205</guid><dc:creator><![CDATA[cyberian]]></dc:creator><pubDate>Fri, 31 May 2024 14:33:37 GMT</pubDate></item><item><title><![CDATA[Reply to MTH603 Quiz 1 Solution and Discussion on Fri, 31 May 2024 14:33:25 GMT]]></title><description><![CDATA[<p dir="auto">Using the Jacobi method find all the eigenvalues and the corresponding 2 eigenvectors of the matrix A = 2 1 2 Iterate till the oR- ~1 2 diagonal elements, in magnitude; are less than 0.0005<br />
Using the Jacobi method find all the eigenvalues and the corresponding 2 eigenvectors of the matrix A = 2 1 2 Iterate till the oR- ~1 2 diagonal elements, in magnitude; are less than 0.0005</p>
]]></description><link>https://community.secnto.com//post/7204</link><guid isPermaLink="true">https://community.secnto.com//post/7204</guid><dc:creator><![CDATA[cyberian]]></dc:creator><pubDate>Fri, 31 May 2024 14:33:25 GMT</pubDate></item><item><title><![CDATA[Reply to MTH603 Quiz 1 Solution and Discussion on Fri, 31 May 2024 14:32:52 GMT]]></title><description><![CDATA[<p dir="auto"><a class="plugin-mentions-user plugin-mentions-a" href="/user/cyberian" aria-label="Profile: cyberian">@<bdi>cyberian</bdi></a> said in <a href="/post/7202">MTH603 Quiz 1 Solution and Discussion</a>:</p>
<blockquote>
<p dir="auto">Here is a table of iterations. The actual vector U is horizontal written as entry 1 and 2, and the current approximation to the first eigenvalue is in the third column. The first(largest in absolute value) eigenvalue is negative, so the system needs a certain time to reduce oscillations:</p>
<table class="table table-bordered table-striped">
<tbody>
<tr>
<td>U[1]</td>
<td>U[2]</td>
<td>eigenvalue</td>
</tr>
<tr>
<td>1</td>
<td>0</td>
<td>0</td>
</tr>
<tr>
<td>1</td>
<td>3</td>
<td>1</td>
</tr>
<tr>
<td>1</td>
<td>-9/7</td>
<td>7</td>
</tr>
<tr>
<td>1</td>
<td>-57/11</td>
<td>-11/7</td>
</tr>
<tr>
<td>1</td>
<td>-261/103</td>
<td>-103/11</td>
</tr>
<tr>
<td>1</td>
<td>-1353/419</td>
<td>-419/103</td>
</tr>
<tr>
<td>1</td>
<td>-6669/2287</td>
<td>-2287/419</td>
</tr>
</tbody>
</table>
</blockquote>
<p dir="auto">in float reprecentation</p>
<table class="table table-bordered table-striped">
<tbody>
<tr>
<td>U[1]</td>
<td>U[2]</td>
<td>eigenvalue</td>
</tr>
</tbody>
<tbody>
<tr>
<td>1.0000000</td>
<td>0</td>
<td>0</td>
</tr>
<tr>
<td>1.0000000</td>
<td>3.0000000</td>
<td>1.0000000</td>
</tr>
<tr>
<td>1.0000000</td>
<td>-1.2857143</td>
<td>7.0000000</td>
</tr>
<tr>
<td>1.0000000</td>
<td>-5.1818182</td>
<td>-1.5714286</td>
</tr>
<tr>
<td>1.0000000</td>
<td>-2.5339806</td>
<td>-9.3636364</td>
</tr>
<tr>
<td>1.0000000</td>
<td>-3.2291169</td>
<td>-4.0679612</td>
</tr>
<tr>
<td>1.0000000</td>
<td>-2.9160472</td>
<td>-5.4582339</td>
</tr>
<tr>
<td>1.0000000</td>
<td>-3.0347480</td>
<td>-4.8320944</td>
</tr>
<tr>
<td>1.0000000</td>
<td>-2.9862913</td>
<td>-5.0694960</td>
</tr>
<tr>
<td>1.0000000</td>
<td>-3.0055137</td>
<td>-4.9725827</td>
</tr>
<tr>
<td>1.0000000</td>
<td>-2.9977994</td>
<td>-5.0110274</td>
</tr>
<tr>
<td>1.0000000</td>
<td>-3.0008810</td>
<td>-4.9955987</td>
</tr>
</tbody>
</table>
]]></description><link>https://community.secnto.com//post/7203</link><guid isPermaLink="true">https://community.secnto.com//post/7203</guid><dc:creator><![CDATA[cyberian]]></dc:creator><pubDate>Fri, 31 May 2024 14:32:52 GMT</pubDate></item><item><title><![CDATA[Reply to MTH603 Quiz 1 Solution and Discussion on Fri, 31 May 2024 14:31:22 GMT]]></title><description><![CDATA[<p dir="auto">Here is a table of iterations. The actual vector U is horizontal written as entry 1 and 2, and the current approximation to the first eigenvalue is in the third column. The first(largest in absolute value) eigenvalue is negative, so the system needs a certain time to reduce oscillations:</p>
<table class="table table-bordered table-striped">
<tbody>
<tr>
<td>U[1]</td>
<td>U[2]</td>
<td>eigenvalue</td>
</tr>
<tr>
<td>1</td>
<td>0</td>
<td>0</td>
</tr>
<tr>
<td>1</td>
<td>3</td>
<td>1</td>
</tr>
<tr>
<td>1</td>
<td>-9/7</td>
<td>7</td>
</tr>
<tr>
<td>1</td>
<td>-57/11</td>
<td>-11/7</td>
</tr>
<tr>
<td>1</td>
<td>-261/103</td>
<td>-103/11</td>
</tr>
<tr>
<td>1</td>
<td>-1353/419</td>
<td>-419/103</td>
</tr>
<tr>
<td>1</td>
<td>-6669/2287</td>
<td>-2287/419</td>
</tr>
</tbody>
</table>
]]></description><link>https://community.secnto.com//post/7202</link><guid isPermaLink="true">https://community.secnto.com//post/7202</guid><dc:creator><![CDATA[cyberian]]></dc:creator><pubDate>Fri, 31 May 2024 14:31:22 GMT</pubDate></item><item><title><![CDATA[Reply to MTH603 Quiz 1 Solution and Discussion on Fri, 31 May 2024 14:28:57 GMT]]></title><description><![CDATA[<p dir="auto">I’m slightly confused about how to use the power method and the steps to calculate an eigenvalue. - I understand that the power method is defined as U(x+1) = AU(x)/a(x) where “a” is the first component of U(x). I do not understand at all what “U” is. Are we picking any vector we want that minimizes the error? What would I do given the practice problem below?</p>
<p dir="auto">Apply the power method to<br />
132−4<br />
1	2	3	−4</p>
<p dir="auto">to obtain three approximations of the largest eigenvalue of A. What is the limiting vector u∞?</p>
]]></description><link>https://community.secnto.com//post/7201</link><guid isPermaLink="true">https://community.secnto.com//post/7201</guid><dc:creator><![CDATA[cyberian]]></dc:creator><pubDate>Fri, 31 May 2024 14:28:57 GMT</pubDate></item><item><title><![CDATA[Reply to MTH603 Quiz 1 Solution and Discussion on Fri, 31 May 2024 14:28:14 GMT]]></title><description><![CDATA[<p dir="auto">while using jacobi method for the matrix a=[2 0 0 02 1 0 1 2] o=pi/4</p>
]]></description><link>https://community.secnto.com//post/7200</link><guid isPermaLink="true">https://community.secnto.com//post/7200</guid><dc:creator><![CDATA[cyberian]]></dc:creator><pubDate>Fri, 31 May 2024 14:28:14 GMT</pubDate></item><item><title><![CDATA[Reply to MTH603 Quiz 1 Solution and Discussion on Fri, 10 May 2024 06:12:29 GMT]]></title><description><![CDATA[<p dir="auto"><a class="plugin-mentions-user plugin-mentions-a" href="/user/anas-khan" aria-label="Profile: anas-khan">@<bdi>anas-khan</bdi></a> please post into relevant category</p>
]]></description><link>https://community.secnto.com//post/7198</link><guid isPermaLink="true">https://community.secnto.com//post/7198</guid><dc:creator><![CDATA[cyberian]]></dc:creator><pubDate>Fri, 10 May 2024 06:12:29 GMT</pubDate></item><item><title><![CDATA[Reply to MTH603 Quiz 1 Solution and Discussion on Tue, 07 May 2024 05:59:29 GMT]]></title><description><![CDATA[<p dir="auto">Please Madam Answer This question.<br />
Total Marks	5<br />
Starting Date	Friday, May 03, 2024<br />
Closing Date	Wednesday, May 08, 2024<br />
Status	Open<br />
Question Title	Graded Discussion Board<br />
Question Description	<br />
Graded Discussion Board for Elementary English (ENG001) will be open from May 3, 2024, to May 8, 2024.</p>
<p dir="auto">Give your opinion on this statement in 200 to 250 words.</p>
<p dir="auto">A good writer is an architect of imagination, constructing worlds with carefully chosen bricks of language. How far do you agree with this statement?</p>
<p dir="auto">Read the following instructions carefully before posting your comments:</p>
<ol>
<li>
<p dir="auto">Write your own views about the topic. Your comments should NOT exceed 200-250 words.</p>
</li>
<li>
<p dir="auto">GDB carries 2% weightage in your final assessment.</p>
</li>
<li>
<p dir="auto">Your comments should be clear, concise, and relevant to the topic.</p>
</li>
<li>
<p dir="auto">Creative and original ideas written in correct English will be highly appreciated.</p>
</li>
<li>
<p dir="auto">For questions or queries related to the topic, you may send us a ticket through ticketing management system.</p>
</li>
<li>
<p dir="auto">Do not send your comments via e-mail or regular MDB.</p>
</li>
<li>
<p dir="auto">The comments posted on regular MDB will not be graded.</p>
</li>
<li>
<p dir="auto">Do not post your comments twice.</p>
</li>
<li>
<p dir="auto">No marks will be awarded for plagiarism.</p>
</li>
</ol>
<p dir="auto">Best of luck!</p>
<p dir="auto">Team ENG001</p>
]]></description><link>https://community.secnto.com//post/7197</link><guid isPermaLink="true">https://community.secnto.com//post/7197</guid><dc:creator><![CDATA[anas khan]]></dc:creator><pubDate>Tue, 07 May 2024 05:59:29 GMT</pubDate></item><item><title><![CDATA[Reply to MTH603 Quiz 1 Solution and Discussion on Mon, 06 May 2024 11:29:42 GMT]]></title><description><![CDATA[<p dir="auto">if the relaxation method is applied on the system</p>
]]></description><link>https://community.secnto.com//post/7196</link><guid isPermaLink="true">https://community.secnto.com//post/7196</guid><dc:creator><![CDATA[cyberian]]></dc:creator><pubDate>Mon, 06 May 2024 11:29:42 GMT</pubDate></item><item><title><![CDATA[Reply to MTH603 Quiz 1 Solution and Discussion on Mon, 06 May 2024 11:29:28 GMT]]></title><description><![CDATA[<p dir="auto">Which of the following rearrangement make strictly diagonal dominant, the system of linear</p>
]]></description><link>https://community.secnto.com//post/7195</link><guid isPermaLink="true">https://community.secnto.com//post/7195</guid><dc:creator><![CDATA[cyberian]]></dc:creator><pubDate>Mon, 06 May 2024 11:29:28 GMT</pubDate></item><item><title><![CDATA[Reply to MTH603 Quiz 1 Solution and Discussion on Mon, 06 May 2024 11:28:39 GMT]]></title><description><![CDATA[<p dir="auto">Which of the following rearrangements make the system of linear equations strictly diagonally dominant: 39 + 2 = -2 62 + 4y + 11z = 1 5r - 23 - 22 = 9 Select one: 2v - 22 = 9 3y = 2 6z + 4y + M = 1 6r + 4y + M = 1 -8v + 2 = -2 51 - %0 - 22 = 0 61 - %v - 28 - 0 Av + M2 = 30 + 2 = -2 No need to rearrange as the system is already diagonally dominant.<br />
Which of the following rearrangements make the system of linear equations strictly diagonally dominant:<br />
39 + 2 = -2<br />
62 + 4y + 11z = 1<br />
5r - 23 - 22 = 9</p>
<p dir="auto">Select one:<br />
2v - 22 = 9<br />
3y = 2<br />
6z + 4y + M = 1<br />
6r + 4y + M = 1<br />
-8v + 2 = -2<br />
51 - %0 - 22 = 0<br />
61 - %v - 28 - 0 Av + M2 = 30 + 2 = -2</p>
<p dir="auto">No need to rearrange as the system is already diagonally dominant.</p>
]]></description><link>https://community.secnto.com//post/7194</link><guid isPermaLink="true">https://community.secnto.com//post/7194</guid><dc:creator><![CDATA[cyberian]]></dc:creator><pubDate>Mon, 06 May 2024 11:28:39 GMT</pubDate></item><item><title><![CDATA[Reply to MTH603 Quiz 1 Solution and Discussion on Mon, 06 May 2024 11:27:54 GMT]]></title><description><![CDATA[<p dir="auto"><a class="plugin-mentions-user plugin-mentions-a" href="/user/cyberian" aria-label="Profile: cyberian">@<bdi>cyberian</bdi></a> said in <a href="/post/7192">MTH603 Quiz 1 Solution and Discussion</a>:</p>
<blockquote>
<p dir="auto">gauss seidel method also known as?</p>
</blockquote>
<p dir="auto">Gauss–Seidel method is an improved form of Jacobi method, also known as the successive displacement method. This method is named after Carl Friedrich Gauss (Apr.</p>
]]></description><link>https://community.secnto.com//post/7193</link><guid isPermaLink="true">https://community.secnto.com//post/7193</guid><dc:creator><![CDATA[cyberian]]></dc:creator><pubDate>Mon, 06 May 2024 11:27:54 GMT</pubDate></item><item><title><![CDATA[Reply to MTH603 Quiz 1 Solution and Discussion on Mon, 06 May 2024 11:27:34 GMT]]></title><description><![CDATA[<p dir="auto">gauss seidel method also known as?</p>
]]></description><link>https://community.secnto.com//post/7192</link><guid isPermaLink="true">https://community.secnto.com//post/7192</guid><dc:creator><![CDATA[cyberian]]></dc:creator><pubDate>Mon, 06 May 2024 11:27:34 GMT</pubDate></item><item><title><![CDATA[Reply to MTH603 Quiz 1 Solution and Discussion on Mon, 06 May 2024 11:27:03 GMT]]></title><description><![CDATA[<p dir="auto">In … method, the elements above and below the diagonal are simultaneously made zero.</p>
]]></description><link>https://community.secnto.com//post/7191</link><guid isPermaLink="true">https://community.secnto.com//post/7191</guid><dc:creator><![CDATA[cyberian]]></dc:creator><pubDate>Mon, 06 May 2024 11:27:03 GMT</pubDate></item><item><title><![CDATA[Reply to MTH603 Quiz 1 Solution and Discussion on Wed, 21 Jun 2023 06:15:24 GMT]]></title><description><![CDATA[<p dir="auto"><a class="plugin-mentions-user plugin-mentions-a" href="/user/cyberian" aria-label="Profile: cyberian">@<bdi>cyberian</bdi></a> said in <a href="/post/7081">MTH603 Quiz 1 Solution and Discussion</a>:</p>
<blockquote>
<p dir="auto">while using relaxation method, which of th folowing is the</p>
</blockquote>
<p dir="auto">2x+3y = 1, 3x +2y =4 ?<br />
<strong>(1,4)</strong></p>
]]></description><link>https://community.secnto.com//post/7094</link><guid isPermaLink="true">https://community.secnto.com//post/7094</guid><dc:creator><![CDATA[cyberian]]></dc:creator><pubDate>Wed, 21 Jun 2023 06:15:24 GMT</pubDate></item><item><title><![CDATA[Reply to MTH603 Quiz 1 Solution and Discussion on Wed, 21 Jun 2023 06:08:00 GMT]]></title><description><![CDATA[<p dir="auto"><a class="plugin-mentions-user plugin-mentions-a" href="/user/cyberian" aria-label="Profile: cyberian">@<bdi>cyberian</bdi></a> said in <a href="/post/7083">MTH603 Quiz 1 Solution and Discussion</a>:</p>
<blockquote>
<p dir="auto">the linear equation 2x-0y-2=0 has</p>
</blockquote>
<p dir="auto"><img src="https://i.imgur.com/Yhr7Y66.png" alt="c01fab1a-1b9b-4bff-b820-e89da0f3dd81-image.png" class=" img-fluid img-markdown" /></p>
]]></description><link>https://community.secnto.com//post/7093</link><guid isPermaLink="true">https://community.secnto.com//post/7093</guid><dc:creator><![CDATA[cyberian]]></dc:creator><pubDate>Wed, 21 Jun 2023 06:08:00 GMT</pubDate></item></channel></rss>