<?xml version="1.0" encoding="UTF-8"?><rss xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:content="http://purl.org/rss/1.0/modules/content/" xmlns:atom="http://www.w3.org/2005/Atom" version="2.0"><channel><title><![CDATA[To apply Simpson&#x27;s 3&#x2F;8 rule, the number of intervals be]]></title><description><![CDATA[<p dir="auto">Answer<br />
10<br />
11<br />
12<br />
13</p>
]]></description><link>https://community.secnto.com//topic/2660/to-apply-simpson-s-3-8-rule-the-number-of-intervals-be</link><generator>RSS for Node</generator><lastBuildDate>Tue, 09 Jun 2026 00:12:07 GMT</lastBuildDate><atom:link href="https://community.secnto.com//topic/2660.rss" rel="self" type="application/rss+xml"/><pubDate>Wed, 09 Oct 2024 08:31:44 GMT</pubDate><ttl>60</ttl><item><title><![CDATA[Reply to To apply Simpson&#x27;s 3&#x2F;8 rule, the number of intervals be on Wed, 09 Oct 2024 08:33:49 GMT]]></title><description><![CDATA[<p dir="auto"><a class="plugin-mentions-user plugin-mentions-a" href="/user/zaasmi" aria-label="Profile: zaasmi">@<bdi>zaasmi</bdi></a> said in <a href="/post/7860">To apply Simpson's 3/8 rule, the number of intervals be</a>:</p>
<blockquote>
<p dir="auto">Answer<br />
10<br />
11<br />
12<br />
13</p>
</blockquote>
<p dir="auto">To apply Simpson’s 3/8 rule, the number of intervals must be a multiple of 3.</p>
<p dir="auto">Among the given options, the correct choice is 12, as it is divisible by 3. This rule approximates the integral using cubic polynomials over sets of three intervals, so the total number of intervals should be a multiple of 3 for the rule to apply.</p>
]]></description><link>https://community.secnto.com//post/7861</link><guid isPermaLink="true">https://community.secnto.com//post/7861</guid><dc:creator><![CDATA[zaasmi]]></dc:creator><pubDate>Wed, 09 Oct 2024 08:33:49 GMT</pubDate></item></channel></rss>