In integrating $\int_{0}^{\frac{2}{2}} \cos x d x$ by dividing the interval into four equal parts, width of the interval should be

Answer
$\frac{\pi}{2}$
$\pi$
$\frac{\pi}{8}$

To determine the width of each interval for the integral \int_{0}^{\frac{\pi}{2}} \cos x , dx  by dividing the interval into four equal parts, we use the formula:

h = \frac{b - a}{n}

where:

•	a = 0,
•	b = \frac{\pi}{2},
•	n = 4.

Calculating h:

h = \frac{\frac{\pi}{2} - 0}{4} = \frac{\frac{\pi}{2}}{4} = \frac{\pi}{8}

So, the width of the interval should be \frac{\pi}{8} .

Thus, the correct answer is \frac{\pi}{8} .