<?xml version="1.0" encoding="UTF-8"?><rss xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:content="http://purl.org/rss/1.0/modules/content/" xmlns:atom="http://www.w3.org/2005/Atom" version="2.0"><channel><title><![CDATA[The (n + 1) th difference of a polynomial of degree n is...]]></title><description><![CDATA[<p dir="auto">The (n + 1) th difference of a polynomial of degree n is…<br />
Answer<br />
0<br />
Constant<br />
n +1</p>
]]></description><link>https://community.secnto.com//topic/2669/the-n-1-th-difference-of-a-polynomial-of-degree-n-is</link><generator>RSS for Node</generator><lastBuildDate>Mon, 08 Jun 2026 22:41:46 GMT</lastBuildDate><atom:link href="https://community.secnto.com//topic/2669.rss" rel="self" type="application/rss+xml"/><pubDate>Wed, 09 Oct 2024 09:23:01 GMT</pubDate><ttl>60</ttl><item><title><![CDATA[Reply to The (n + 1) th difference of a polynomial of degree n is... on Wed, 09 Oct 2024 09:24:15 GMT]]></title><description><![CDATA[<p dir="auto"><a class="plugin-mentions-user plugin-mentions-a" href="/user/zaasmi" aria-label="Profile: zaasmi">@<bdi>zaasmi</bdi></a> said in <a href="/post/7878">The (n + 1) th difference of a polynomial of degree n is...</a>:</p>
<blockquote>
<p dir="auto">The (n + 1) th difference of a polynomial of degree n is…<br />
Answer<br />
0<br />
Constant<br />
n +1</p>
</blockquote>
<p dir="auto">The (n + 1) difference of a polynomial of degree n is 0.</p>
<p dir="auto">This is because the differences eventually reach a constant value after taking differences equal to the degree of the polynomial plus one. Therefore, for a polynomial of degree n ￼, the (n + 1) difference will always be zero.</p>
<p dir="auto">Thus, the correct answer is 0.</p>
]]></description><link>https://community.secnto.com//post/7879</link><guid isPermaLink="true">https://community.secnto.com//post/7879</guid><dc:creator><![CDATA[zareen]]></dc:creator><pubDate>Wed, 09 Oct 2024 09:24:15 GMT</pubDate></item></channel></rss>