Solution:
Customer(Customer_ID, Name, Address, Contact_No, email)
Order(Order_ID, Order_Status, Delivery_Date, Customer_ID, Manager_ID,Sman_ID)
Bill(Bill_ID, Order_ID, Amount, date)
Bottle(Bottle_Tag_No, Fillling_Date, Expiry_Date, Capacity, Order_ID)
Manager(Manager_ID, Name, Address)
Salesman(Sman_ID, Name, Contact_No)
SalesArea(Area_ID, Area_Name, Sman_ID)

2. Consider the following two tables:

Order:

Bill:

And write the output of the following relational algebra operations:

• ∏ order_id, cust_id, sman_id (Order)

• σ net_amount > 500 (Bill)

• ∏ order_status, delivery_date, (σ btag_no=’bt002’ (Order))

3. Find the degree and cardinality of the relations (Order and Bill) given in the 2nd question.

Solution:
Customer(Customer_ID, Name, Address, Contact_No, email)
Order(Order_ID, Order_Status, Delivery_Date, Customer_ID, Manager_ID,Sman_ID)
Bill(Bill_ID, Order_ID, Amount, date)
Bottle(Bottle_Tag_No, Fillling_Date, Expiry_Date, Capacity, Order_ID)
Manager(Manager_ID, Name, Address)
Salesman(Sman_ID, Name, Contact_No)
SalesArea(Area_ID, Area_Name, Sman_ID)

2. Consider the following two tables:

Order:

Bill:

And write the output of the following relational algebra operations:

• ∏ order_id, cust_id, sman_id (Order)

• σ net_amount > 500 (Bill)

• ∏ order_status, delivery_date, (σ btag_no=’bt002’ (Order))

3. Find the degree and cardinality of the relations (Order and Bill) given in the 2nd question.

Question No 2:
Order:
order_id order_status delivery_date btag_no cust_id sman_id
od001 Completed 10/30/2019 bt001 cust001 sm001
od002 Completed 10/30/2019 bt002 cust002 sm001
od003 Completed 10/30/2019 bt003 cust003 sm001
Bill:
bill_id cust_id order_id net_amount
b001 cust001 od001 500
b002 cust002 od002 550
b003 cust001 od003 600

And write the output of the following relational algebra operations:
• ∏ order_id, cust_id, sman_id (Order)
•
∏ Operator name is projection this is used to select all the colum in the table
It will select three colums, order_id, sman_id and cust_id. It also delete the unwanted colums on the basis of condition
• σ net_amount > 500 (Bill)
σ is used for selection. it select the subset of rows from table answer will be second and third row from bill table answer will be (550,600)
• ∏ order_status, delivery_date (σ btag_no= ‘bt002’ (Order))
In this it will first perform the selection and select the btag no row from order table then projection will be performed and in projection it will selct the colum order-status value and delivery date value where btag no is bt002.
Answer will be order status delivery date
Completed 10/30/2019

Question no 3:

1. Find the degree and cardinality of the relations (Order and Bill) given in the 2nd question.
   (a)
   Degree = number of attributes or colums in the table is his degree
   Order table have 6 colums/attributes so its degree will be 6
   Bill table have 4 colums/attributes so its degree will be 4
   Degree of the (Order and Bill) will be
   Degree -> 6+4=10
   (b)
   Cardinality = numbers of tuples/rows in the table
   Number of rows in order table = 3
   Number of rows in bill table =3
   Cardinality of order and bill (rowsrows)
   Cardinality -> 33 =9